I mean I wonder how many vertical feet the new ramp extension will be.
I mean I wonder how many vertical feet the new ramp extension will be.
It's not common core math and not to difficult to compute. It's a 120 ft ramp extension at a 14% grade. 100 ft @ 14%=14 ft. A 120 ft ramp extension @ 14%=16.8 ft. I gave you a hint on my original answer that 100 ft length was 14 ft drop.
Oh. My guess was 12 feet.
For the common core math challenged:
If the original ramp is 490 ft long and the first extension added is 250 ft long and the new extension will be 120 ft. How many feet to the end of the total ramp length and how far under water at a 14% grade will the end be from the top of the ramp?
Last edited by DEVOREFLYER; 05-22-2015 at 02:15 PM.
....Long enough and Too deep?
Huh, my brain hurts! I just hope it'll be usable sometime this year.
The total length of the ramp after its completion will be 860 lineal feet. When the lake is at full pool, the water line is roughly 20-30 lineal feet below the top of the ramp so one must deduct that from the total length of the ramp. So the actual vertical distance the end of the ramp that is under water is;
490
+
250
+
120=860
-
25 lineal feet to full pool water line(x 14%= 3.5 vertical feet) = 835 total lineal feet of ramp under water
x
a 14% pitch=116.9 vertical feet under water at full pool. It's elementary, really...
Last edited by HawgZWylde; 05-22-2015 at 03:32 PM.